The aim of my work was:
1. How long does it take my pellet to move from stationary position at breech to emerge 150 m/sec (500 fps approx) at the muzzle
2. What force is required to accelerate the pellet to that velocity
3. What is the air pressure that needs to be achieved by the piston to get that pressure?
4. What is the minimum speed the piston must travel at to get that pressure?
For the calculations I needed several measurements and I will simply list them here minus the calculation. If anyone is interested I will post the actual formulae I used in a separate post. Most 12th std kids will know them although most others forget - except engineers I guess. They can be used to do the same calculation for any air rifle if other parameters listed below are known.
1. Area of bore of rifle (0.22)= 0.16 sq cm
2. Length of barrel: 50 cm
3. Volume of air in barrel: 8 cc
4. Piston face area: 5 sq cm (from piston diameter of 2.5 cm)
5. Length of piston stroke: 7 cm
6. Volume of air in piston chamber (cocked): 35 cc
7. Muzzle velocity: 150 m/sec
8. Weight of pellet= 700 mg (approx 11 grains)
From these it is possible to calculate that:
1.The pellet takes just 7/1000 of a second (0.0066 sec) to exit the barrel at 150 m/sec
2. The piston has to be faster than that and assuming that the piston compresses the air in just 0.0025 sec it means that the piston is traveling at 96 kmph (60 mph). This fits in with some data I found on a Pyramid air site - but my calculation cannot be taken as exact. It is guesswork.
3. The pressure required to push the pellet out at that velocity is theoretically 97 times atmospheric pressure (97 bar). (The force is 157 Newtons). To make the pellet go supersonic (330 m/sec) I would need a force of 762 Newtons or 470 bar pressure - i.e 470 times atmospheric pressure.
4. A pressure of 97 bar can be achieved by the piston only when the air in the chamber is compressed to a volume that is 97 times smaller than the original 35 cc - i.e at a point when the piston is almost hitting the breech end of the chamber. But at 97 bar the air is pressing back at the piston face with a 500 kg force so the piston cannot slam into the back of the breech so easily. Even in the "worst case" scenario of pellet being very close to muzzle when the piston hits the breech, there will still be at least 20-25 kg force holding the piston back from slamming hard into the front of the chamber.
5. In reality the dynamics will be a little different because the air pressure will rise a lot more due to heating, but the pellet also will move forward tending to increase the volume and reduce the pressure.
6. The total time from release of sear to exit of pellet is in the region of 0.01 seconds (or less). Human nerves that sense touch at best transmit impulses at 50 m/sec (often slower). The distance from hand to brain may be 1 meter - so the sensation reaches the brain in 1/50 second - or 0.02 sec. This is a lot slower than the exit time of the pellet so the brain cannot register the time in which the pellet exits until after it is out.
7. Unfortunately I do not know the weight of the piston. If I guess that it is 250 grams and the piston moves at 96 kmph - an empty chamber with no pellet (dry firing) will ensure that the piston hits the front of the chamber with tremendous force. That is the force of a 1 kg weight falling on your toe from a height of 8 feet or so.
